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Integrate an arctangent over a power of d (1 ± i c x) under the tangent - #1918
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Rafael-SOWNet merged 3 commits intoOct 17, 2026
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Under x = tan(u)/c, 1 + i tan(u) is e^(i u)/cos(u), so x^m (a + b atan(c x))^p/(d (1 +- i c x))^k is (a + b u)^p (tan(u)/c)^m d^(-k) e^(-+i k u) cos(u)^(k - 2)/c, a polynomial in u times exponentials and trigonometric functions. Rubi's 5.3.4 (a + b atan(c x))^2/(d + i c d x)^2 and seven like it ran out of time. Part of #718 Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
…a-power-of-one-plus-i-c-x-under-the-tangent # Conflicts: # Sources/AngouriMath/Functions/Continuous/Integration/Integration.Definition.cs
…KING-CHANGES Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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Part of #718.
Under
x = tan(u)/c,1 + i tan(u)ise^(i u)/cos(u). Sox^m (a + b atan(c x))^p/(d (1 ± i c x))^kbecomes(a + b u)^p (tan(u)/c)^m d^(-k) e^(∓i k u) cos(u)^(k - 2)/c, a polynomial inutimes exponentials and trigonometric functions. The new rule is asked early, ahead of the rules that spent the budget.Rubi chain (master arm at 1e79b0e, 5 s budget):
1/((a g+b g x)^2 (A+B log(...))^2), which takes 23 s on both arms when run alone, so it is noise.Gained on 2.5.0: eight rows of 5.3.4 that were all
integral(...). The branch answers them in 267 to 1,202 characters, each in under half a second.🤖 Generated with Claude Code
https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura