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Integrate a linear and a quadratic to one power as one binomial - #1899
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Rafael-SOWNet merged 3 commits intoOct 16, 2026
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Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
…ratic-to-one-power-are-one-binomial # Conflicts: # Sources/AngouriMath/Functions/Continuous/Integration/IndefiniteIntegralSolver.cs
Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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Part of #718.
A linear and a quadratic at one power that is not whole, whose product is
A + B x^3, are integrated as(L^p Q^p/(A + B x^3)^p) · ∫ g (A + B x^3)^p. For example,(1 + x)(1 - x + x^2)is1 + x^3, and the rules for a power of a binomial answer the rest. The quotient is constant on each interval between the roots, for the same reason as in #1897, and the joined integral is checked against the joined integrand.Rubi corpus, against master d05d20d (both arms built and run in one chain; master then moved to 35c9ba5, merged here):
The three are 1.2.1.2:2919, 2922 and 2925, which were declined on master and are answered here in under half a second. There are no losses, no wrong answers, and no solved row more than 2× slower. The performance gate and the unit suite (15,410 passed) pass. The exact check at 50–2,000 digits agrees on all three, including where the cube roots are complex, 60/60.
BREAKING-CHANGES.mdhas an entry for the three, measured on 2.5.0 and on this branch.🤖 Generated with Claude Code
https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura